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PhysicsSHMMiscellaneousHard2 minPYQ_2013
PhysicsHardsingle choice

Two charges, each equal to q , are kept at x = - a and x  =  a on the x-axis. A particle of mass m and chargeq0=-q2is placed at the origin. If charge q 0 is given a small displacement (y << a) along the y-axis, the net force acting on the particle is proportional to :

Question diagram: Two charges, each equal to q , are kept at x = - a and x = a

Options:

Answer:
C
Solution:




F net = 2Fcos θ

Fnet=2kqq2y2+a22yy2+a2

Fnet=2kqq2yy2+a23/2kq2a3yF-y

Net force F is opposite the direction of displacement y. Hence, negative sign is used.

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Miscellaneous
2mℹ️ Source: PYQ_2013

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