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PhysicsSHMOscillationsMedium2 minQB

PhysicsMediuminteger

Find out the time period (sec.) of the system for a small displacement. $[π = 10]$

Answer:

Solution:

The two blocks oscillate together, so use the reduced mass: $μ = \frac{m _{1} m _{2}}{m _{1} + m _{2}} = \frac{3 \times 6}{3 + 6} = 2 kg$

$T = 2 π \frac{μ}{k} = 2 π \frac{2}{80}$

With π = √10: $T = 210 \times \frac{1}{40} = \frac{2 10}{2 10} = 1 s$

Answer: 1

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Oscillations

⏱ 2mℹ️ Source: QB

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