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PhysicsSHMMiscellaneousEasy2 minPYQ_2021

PhysicsEasysingle choice

A particle is performing S.H.M. with maximum velocity ' $v$ '. If the amplitude is tripled and periodic time is doubled then maximum velocity will be

Answer:

Solution:

$V = V_{m a x} = ω A = \frac{2 π}{T} \cdot A$ If $A$ is tripled and $T$ is doubled, $V_{m a x}$ will become $\frac{3}{2}$ times or 1.5 times.

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2021

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