Physics - SHM Question with Solution | TestHub

The given equation is written as,

$y=3\sin \left(100 t+\frac{\pi }{6}\right)$...(i)

The general equation of simple harmonic motion is written as

$y=a\sin (\omega t+\varnothing )$...(ii)

Equating Eqs. (i) and (ii), we get

$a=3, \omega =100$

Maximum velocity,$v=a\mathrm{\omega }$$=3\times 100=300 \mathrm{m }{\mathrm{s}}^{-1}$