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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

This time period of a particle undergoing SHM is $16 s$ . It starts motion from the mean position. After $2 s$ , its velocity is $0.4 m s^{- 1} .$ The amplitude is

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Answer:

Solution:

Velocity, $v = r ω \cos ω t;$

$0.4 = r \times \frac{2 π}{16} \cos �� \frac{2 π}{16} \times 2 = r \times \frac{2 π}{16} \times \frac{1}{\sqrt{2}}$

or $r = \frac{0.4 \times 16 \times \sqrt{2}}{2 π} = \frac{3.2 \sqrt{2}}{π} = 1.44 m$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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