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PhysicsSHMCalculation of time periodMedium2 minPYQ_2021
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A particle is making simple harmonic motion along theX-axis. If at a distancesx1andx2from the mean position the velocities of the particle arev1andv2, respectively. The time period of its oscillation is given as:

Options:

Answer:
D
Solution:

v2=ω2 A2-x2

A2=x12+v12ω2=x22+v22ω2

ω2=v22-v12x12-x22

T=2πx12-x22v22-v12

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period
2mℹ️ Source: PYQ_2021

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