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PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediumsingle choice

A pendulum clock is in a lift accelerating downward at $g /4$ . By what factor does the period change, new/old?

Answer:

Solution:

$g_{e ff} = g - g /4 = 3 g /4$ . $T \propto 1/ g_{e ff}$ , so $T_{n e w} / T = 4/3$ .

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

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