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Physics - SHM Question with Solution | TestHub

PhysicsSHMSpring oscillationMedium2 minQB

PhysicsMediumsingle choice

Two particles $A$ and $B$ of equal masses are suspended from two massless springs of spring constants $K$ and $4 K$ respectively. If the maximum velocities during oscillations are equal, the ratio of the amplitude of $A$ and $B$ is

Options:

Answer:

Solution:

Maximum speed in SHM: $v_{ma x} = A ω = A \frac{K}{m}$

Equal masses and equal maximum velocities: $A_{A} K = A_{B} 4 K$

$\frac{A _{A}}{A _{B}} = \frac{4 K}{K} = 2$

Hence option (D).

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Spring oscillation

⏱ 2mℹ️ Source: QB

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