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PhysicsSHMCalculation of time periodEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle is executing simple harmonic motion with an amplitude $A$ and time period $T$ . The displacement of the particles after $2 T$ period from its initial position is

Options:

Answer:

Solution:

Particle doing SHM repeats its motion after each Time period.

Since $2 T$ is a multiple of time period of the SHM hence particle will be at the position where it stared it's motion time $2 T$ ago.

$∴$ displacement of the particle will be zero

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

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