The ratio of kinetic energy at mean position to potential energy at A 2 ( A is the amplitude) of a particle performing SHM is (Consider the mean position as reference point)

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Kinetic energy K = 1 2 m ω 2 (A 2 - y) 2 At mean position y = 0 K = 1 2 m ω 2 ( A 2 ) Potential energy U = 1 2 m ω 2 y 2 ...(i) U a t y = A 2 U = 1 2 m A 2 4 ω 2 ...(ii) Dividing Eq. (i) by Eq. (ii), we get K U = 4 1

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