Physics - SHM Question with Solution | TestHub

The correct option is (B). Concept: The phase difference given $\varphi =\left(\frac{\pi }{3}\right)$, so we can obtain the distance between two particles by using the path difference: $\mathrm{k}\left({\mathrm{x}}_2-{\mathrm{x}}_1\right)=\varphi$ Where, $\mathrm{k}$ is the propagation constant. The general equation of the wave is given by $\mathrm{y}=\mathrm{A}\sin (\omega \mathrm{t}-\mathrm{kx})$ on comparing with the given equation, $\mathrm{k}=3$ and $\omega =100\pi$. Therefore, the distance between two particles is given by, $\left({\mathrm{x}}_2-{\mathrm{x}}_1\right)=\frac{\varphi }{\mathrm{k}}=\frac{\pi }{9}\mathrm{m}$