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PhysicsSHMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Two bodies $A$ and $B$ of equal mass are suspended from two separate massless springs of constant $k_{1}$ and $k_{2}$ respectively. If the bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of $A$ to that of $B$ is

Options:

Answer:

Solution:

$v_{max} = ωA$

$ω_{A} A_{A} = ω_{B} A_{B}$

$\Rightarrow \frac{A_{A}}{A_{B}} = \frac{ω_{B}}{ω_{A}}$

$\frac{ω_{B}}{ω_{A}} = \sqrt{\frac{k_{2}}{m}} \div \sqrt{\frac{k_{1}}{m}} = \sqrt{\frac{k_{2}}{k_{1}}}$ .

⇒ $\sqrt{\frac{k_{2}}{k_{1}}}$ is correct.

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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