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PhysicsSHMMiscellaneousHard2 minPYQ_2018

PhysicsHardsingle choice

For a particle performing linear SHM, its average speed over one oscillation is ( $A =$ amplitude of S.H.M., $n =$ frequency of oscillation)

Answer:

Solution:

Distance travelled in one oscillation is 4 $A$ and time period is T.
$∴$ average velocity $= \frac{4 A}{T} = 4 A n$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2018

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