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PhysicsSHMMiscellaneousHard2 minPYQ_2015
PhysicsHardsingle choice

A simple harmonic oscillator of angular frequency2 rad s-1is acted upon by an external forceF=sin⁡t N. If the oscillator is at rest in its equilibrium position att=0,its position at later times is proportional to:

Options:

Answer:
C
Solution:

It is given that oscillator at rest att=0i.e. att=0,v=0. So, in option, we can check by puttingv=dxdt=0.

(1)If x∝sin⁡t+12cos⁡2t

⟹v∝cos⁡t+12×2 (-sin⁡2t)

⟹  at t=0, v∝1-0≠0

(2)If x ∝cos⁡t-12sin⁡t

⟹  v∝-sin⁡t-12cos⁡t

⟹at t=0, v∝-12≠0

(3)If x∝sin⁡t-12 sin 2t

then υ∝cos⁡t-12×2cos⁡2t

⟹at t=0, v∝1-1=0

(4)If x∝sin⁡t+12sin⁡2t

⟹v∝cos⁡t+12×2cos⁡2t

⟹at t=0, v∝1+1

⟹  v∝2≠0

∴   in option 3  v=0   at   t=0

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2015

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