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PhysicsSHMEnergyMedium2 minQB

PhysicsMediummultiple choice

Total energy of a particle executing oscillating motion is 3 joule and given by

Answer:

C, D

Solution:

Complete the squares: $E = (x + 1)^{2} + (v - 1)^{2} - 2 = 3$

At the extremes v = 0: $(x + 1)^{2} = 4 \Rightarrow x = 1 or - 3$ ; mean position x = -1, so amplitude = 2 m (C correct).

At the mean position x = -1: $(v - 1)^{2} = 5 \Rightarrow v_{ma x} = 5 + 1 m / s$ (D correct).

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Energy

⏱ 2mℹ️ Source: QB

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