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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousMedium2 minPYQ_2014

PhysicsMediumsingle choice

The time period of a particle undergoing SHM is $16 s$ . It starts motion from the mean position. After $2 s$ , its velocity is $0.4 m s^{- 1}$ . The amplitude is

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Solution:

Velocity, $v = r ω cos ω t$ $0.4 = r \times \frac{2 π}{16} cos \frac{2 π}{16} \times 2 = r \times \frac{2 π}{16} \times \frac{1}{2}$ or $r = \frac{0.4 \times 16 \times 2}{2 π} = \frac{3.2 2}{π} = 1.44 m$

Stream:AIIMSSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2014

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