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PhysicsSHMCalculation of time periodMedium2 minQB

PhysicsMediumsingle choice

Find time period of small oscillations for the given system (as shown in figure).

Answer:

Solution:

Springs $2 K$ and $K$ are in series: $K_{e q} = \frac{2 K \cdot K}{2 K + K} = \frac{2 K}{3}$ .

Reduced mass of the two blocks: $μ = \frac{2 m \cdot m}{2 m + m} = \frac{2 m}{3}$ .

$T = 2 π \frac{μ}{K _{e q}} = 2 π \frac{2 m /3}{2 K /3} = 2 π \frac{m}{K}$ - option (B).

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: QB

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