Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodMedium2 minPYQ_2021

PhysicsMediumsingle choice

Two identical springs of spring constant $2 k$ are attached to a block of mass $m$ and to fixed support (see figure). When the mass is displaced from equilibrium position on either side, it executes simple harmonic motion. The time period of oscillations of this system is :

Options:

Answer:

Solution:

For parallel combination $k_{e q} = k_{1} + k_{2}$

$k_{e q} = 4 k$

$T = 2 π \sqrt{\frac{m}{k_{e q}}} \Rightarrow T = 2 π \sqrt{\frac{m}{4 k}} \Rightarrow T = π \sqrt{\frac{m}{k}}$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...