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PhysicsSHMEnergyMedium2 minPYQ_2010

PhysicsMediumsingle choice

$U$ is the PE of an oscillating particle and $F$ is the force acting on it at a given instant. Which of the following is true ?

Answer:

Solution:

The potential energy, $U = \frac{1}{2} k x^{2}$ $2 U = k x^{2}$ or $2 U = - F x [∵ F = - k x] \frac{2 U}{F} = - x$ or $\frac{2 U}{F} + x = 0$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Energy

⏱ 2mℹ️ Source: PYQ_2010

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