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PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediuminteger

In SHM the graph of $v^{2}$ against $x$ is a parabola that cuts the $v^{2}$ axis at $64$ (cm/s)² and the $x$ axis at $\pm 4$ cm. Find $ω$ in rad/s.

Answer:

Solution:

At $x = 0$ , $v^{2} = ω^{2} A^{2} = 64$ so $v_{ma x} = 8$ cm/s. With $A = 4$ cm, $ω = 8/4 = 2$ rad/s.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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