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Physics - SHM Question with Solution | TestHub

PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediumsingle choice

A body performs SHM along $A BC D E$ ( $C$ the midpoint, $A$ and $E$ the extremes, $A E = 2 R$ ). Its kinetic energy at $B$ and $D$ is $\frac{3}{4}$ of the maximum. Find $B D$ .

Options:

Answer:

Solution:

$\frac{1}{2} k (R^{2} - x^{2}) = \frac{3}{4} \cdot \frac{1}{2} k R^{2}$ gives $x = \pm R /2$ , so $B D = R$ .

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

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