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Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodMedium2 minPYQ_2007

PhysicsMediumsingle choice

A particle executes simple harmonic oscillation with an amplitude $a$ . The period of oscillation is $T$ . The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is:NEET 2007

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Answer:

Solution:

For equilibrium position $x (t) At x (t) ∴ sin (\frac{π}{6}) or \frac{π}{6} \Rightarrow t = a sin ω t = \frac{a}{2} = sin ω t {∵ ω = \frac{2 π}{T}} = \frac{2 π t}{T} = \frac{T}{12}$

Stream:NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2007

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