The bob of a simple pendulum executes simple harmonic motion in water with a period t , while the period of oscillation of the bob is t 0 in air. Neglecting frictional force of water and given that

Question

The bob of a simple pendulum executes simple harmonic motion in water with a period $t$ , while the period of oscillation of the bob is $t_{0}$ in air. Neglecting frictional force of water and given that the density of the bob is $(\frac{4}{3}) \times 1000 kg / m^{3}$ . What relationship between $t$ and $t_{0}$ is true?

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Answer:

C

Solution:

$\frac{T}{T _{0}} = \frac{1}{( 1 - \frac{ρ ^{'}}{ρ} )} = \frac{1}{1 - \frac{1}{3}}$ $\Rightarrow \frac{T}{T _{0}} = 2$ or, $T = 2 T_{0}$

TestHub · Accepted Answer

T 0 ​ T ​ = ( 1 − ρ ρ ′ ​ ) 1 ​ ​ = 1 − 3 1 ​ 1 ​ ​ ⇒ T 0 ​ T ​ = 2 or, T = 2 T 0 ​

Physics - SHM Question with Solution | TestHub

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