Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodHard2 minQB

PhysicsHardsingle choice

A simple pendulum has a time period $T_{1}$ . The point of suspension is now moved upward according to the relation $y = t^{2}$ where y is the vertical displacement. Find the % change in time period ( $g = 10 m / s^{2}$ ) (Given : $12 = 3.46$ )

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Solution:

$y = t^{2}$

$\Rightarrow \frac{d y}{d t} = 2 t \Rightarrow \frac{d ^{2} y}{d t ^{2}} = 2 \Rightarrow a = 2 T_{1} = 2 π \frac{l}{g} T_{2} = 2 π \frac{l}{g + a} % c han g e = (\frac{T _{1} - T _{2}}{T _{1}}) \times 100 = 8.7%$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: QB

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