In an unbiased p-n junction diode, the thickness of the depletion layer is $7 \times 1 0^{- 6} m$ and the potential barrier is $0.7 V$ . What is the average electric field in this region (in $V m^{- 1}$ )?
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Answer:
A
Solution:
$E = \frac{V}{d} = \frac{0.7}{7 \times 1 0 ^{- 6}}$
$E = 1 0^{5} V m^{- 1}$

Question

In an unbiased p-n junction diode, the thickness of the depletion layer is 7 × 1 0 − 6 m and the potential barrier is 0.7 V . What is the average electric field in this region (in V m − 1 )?

TestHub · Accepted Answer

E = d V ​ = 7 × 1 0 − 6 0.7 ​ E = 1 0 5 V m − 1

Physics - Semiconductors Question with Solution | TestHub

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