Figure shows a circuit in which three identical diodes are used. Each diode has forward resistance of $20Ω$ and infinite backward resistance. Resistors $R_{1} = R_{2} = R_{3} = 50Ω$ . Battery voltage is $6 V$ . The current through $R_{3}$ is :

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Here, diodes D 1 ​ and D 2 ​ are forward biased and D 3 ​ is reverse biased. Therefore current through R 3 ​ i = R ′ V ​ = 120 6 ​ = 20 1 ​ A = 50 mA

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