Physics - Semiconductors Question with Solution | TestHub

In the given circuit, the p-side of the silicon diode is connected to the positive terminal of the battery, so it is forward-biased.

The effective voltage across the resistor is the battery voltage minus the knee voltage of the diode:
$V_{\text{eff}}=V-V_k$
$V_{\text{eff}}=5-0.7=4.3\text{ V}$

The current in the circuit is given by Ohm's law:
$I=\frac{V_{\text{eff}}}{R}$
$I=\frac{4.3}{200}\text{ A}$
$I=0.0215\text{ A}$

Converting to milliamperes:
$I=21.5\text{ mA}$

Answer: $21.5$ mA