Physics - Semiconductors Question with Solution | TestHub

If we consider break down in Zener diode, then potential across$R_3$will be$10 \mathrm{V}$and$R_1$will be$2 \mathrm{V}$.

So current in$R_3$will be$i_3=\frac{10}{1500}=\frac{2}{300} \mathrm{A}$

and current in$R_1$will be$i_1=\frac{2}{500} \mathrm{A}$

$\Rightarrow i_1<i_3$, which is not possible

$\Rightarrow$The potential difference across the Zener diode does not reach to break down voltage. So no current will flow through the reverse-biased Zener diode.