If transistor having α = 0.9 , is used in CE configuration, then for a change of 0.4 mA in base current, what will be the change in collector current?

Question

TestHub · Accepted Answer

The current gain in common emitter configuration is given by $β = \frac{α}{1 - α}$ .

Substituting $α = 0.9$ :

$β = \frac{0.9}{1 - 0.9} = \frac{0.9}{0.1} = 9$

The change in collector current is related to the change in base current by $Δ I_{C} = β Δ I_{B}$ .

Given $Δ I_{B} = 0.4$ mA:

$Δ I_{C} = 9 \times 0.4 = 3.6$ mA.

Physics - Semiconductors Question with Solution | TestHub

Options:

Doubts & Discussion