In a common emitter transistor amplifier, signal voltage across the collector resistance of 2 k Ω is 2 volt . What should be the value of resistance R B in series with V B B voltage supply of 2 volt i

Question

In a common emitter transistor amplifier, signal voltage across the collector resistance of $2 k Ω$ is $2 volt$ . What should be the value of resistance $R_{B}$ in series with $V_{B B}$ voltage supply of $2 volt$ in the input circuit, if the $D . C .$ base current is $10$ times the signal current in $R_{B}$ ?

$($ given base emitter voltage $V_{B E} = 0.6$ volt, current amplification factor $β_{a c} \approx β_{d c} = 100$ $)$

TestHub · Accepted Answer

i c AC = V out AC R C = 2 volt 2 kΩ = 1 mA i B AC = i c AC β ac = 1 mA 100 = 0 . 01 mA i B DC = 10 i B AC = 0 . 1 mA = 10 - 4 A R B = V i B = 2 - 0 . 6 10 - 4 = 14 kΩ

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