Physics - Semiconductors Question with Solution | TestHub

The potential at the p-side of the diode is $3\text{ V}$ and the potential at the n-side (through the resistor) is $1\text{ V}$.

Since the p-side is at a higher potential than the n-side, the diode is forward-biased.

An ideal diode in forward bias acts as a short circuit with zero resistance and zero voltage drop.

The potential difference across the resistor is:
$\Delta V=3\text{ V}-1\text{ V}=2\text{ V}$

Using Ohm's law, the current $I$ in the circuit is:
$I=\frac{\Delta V}{R}=\frac{2}{100}\text{ A}$

$I=0.02\text{ A}=20\text{ mA}$

Answer: 20 mA