Physics - Semiconductors Question with Solution | TestHub

The given logic circuit consists of an AND gate, a NOT gate, and an OR gate.

The inputs $A$ and $B$ are connected to the AND gate. The output of this AND gate is $A\cdot B$.

The input $C$ is connected to the NOT gate. The output of this NOT gate is $\bar{C}$.

These two signals, $A\cdot B$ and $\bar{C}$, are fed as inputs to the OR gate.

The final output $Y$ is the logical OR of these two inputs, which gives:
$Y=(A\cdot B)+\bar{C}$

Answer: $Y=(A\cdot B)+\bar{C}$