Physics - Semiconductors Question with Solution | TestHub

The gate circuit can be shown by giving two inputs $A$ and $B$.Output of NOR gate, $Y_1=\overline{A+B}$ Output of NAND gate, $\begin{array}{rl}{Y}_2& =\overline{Y_1\cdot Y_1}\\ & =\overline{\overline{A+B}\cdot \overline{A+B}}\\ & =\overline{\overline{A+B}}+\overline{\overline{A+B}}\\ & =(A+B)+(A+B)\\ & =A+B\end{array}$ Output of NOT gate, $\begin{array}{rl}Y& =\overline{Y_2}\\ & =\overline{A+B}\end{array}$ which is the output of NOR gate. Altemative :Same as NOR Gate NOR Gate $\begin{array}{lll}0& 0& 1\\ 0& 1& 0\\ 1& 0& 0\\ 1& 1& 0\end{array}$ Note : NOR and NAND gates are said to be universal building blocks.