Physics - Semiconductors Question with Solution | TestHub

In an n-p-n transistor 200 electrons enter the emitter in $10^{-8}$ second. If $1\%$ electrons are lost in the base, then the current that enters the emitter and the current amplification factor are respectively $\left[\mathrm{e}=1.6\times 10^{-19}\mathrm{C}\right]$