Physics - Semiconductors Question with Solution | TestHub

From the given logic circuit diagram, we can identify the logic gates and their corresponding Boolean expressions:

1. The gate producing $Y_1$ is an OR gate with inputs $A$ and $B$.
Therefore, $Y_1=A+B$

2. The gate with inputs $C$ and $D$ is a NAND gate, so its output is $\overline{C\cdot D}$. This output is fed into a NOT gate to produce $Y_2$.
Therefore, $Y_2=\overline{\overline{C\cdot D}}=C\cdot D$

3. The final gate producing $Y_3$ is a NOR gate with inputs $Y_1$ and $Y_2$.
Therefore, $Y_3=\overline{Y_1+Y_2}$

When all inputs are changed to 'zero', i.e., $A=0,B=0,C=0,D=0$:
$Y_1=0+0=0$
$Y_2=0\cdot 0=0$
$Y_3=\overline{0+0}=\overline{0}=1$

Thus, the outputs $(Y_1,Y_2,Y_3)$ are $(0,0,1)$.

Answer: $(0,0,1)$