The given truth table relates Y to A and B . A B Y 0 0 1 0 1 0 1 0 0 1 1 0 Then, Y is given by

A B Y 0 0 1 0 1 0 1 0 0 1 1 0 A + B ¯ = 0 + 0 ¯ = 1 0 + 1 ¯ = 0 1 + 0 ¯ = 0 1 + 1 ¯ = 0

Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsLogic gatesEasy2 minPYQ_2020

PhysicsEasysingle choice

The given truth table relates $Y$ to $A$ and $B$ .

Then, $Y$ is given by

Answer:

Solution:

$\bar{A + B} = \bar{0 + 0} = 1$

$\bar{0 + 1} = 0$

$\bar{1 + 0} = 0$

$\bar{1 + 1} = 0$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SemiconductorsSubtopic:Logic gates

⏱ 2mℹ️ Source: PYQ_2020

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