A thin uniform hemispherical bowl of mass $m$ and radius $R$ is lying on a smooth horizontal surface. A horizontal force $F$ is now applied perpendicular to the rim of the bowl (see figure). The instantaneous angular acceleration of the bowl will be :-

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Wrt COM of hemisphere ​ Torque = I com ​ ⋅ α ​ ​ ​ ​ ​ F ⋅ 2 R ​ = I co m ​ α F ⋅ 2 R ​ = [ 3 2 ​ M R 2 − m ( 2 R ​ ) 2 ] α O n so l v in g α = 5 MR 6 F ​

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