Physics - Rotation Question with Solution | TestHub

PhysicsRotationRotational KinematicsMedium2 minQB

PhysicsMediumsingle choice

A 20 kg cabinet is mounted on small casters that allow it to move freely (μ = 0) on the floor. If a 100 N force is applied as shown.The acceleration (in $m / s^{2}$ ) of the cabinet is :-

Options:

Answer:

Solution:

$a = \frac{F}{m}$

$a = \frac{100 N}{20 k g}$

$a = 5 m / s^{2}$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...