Physics - Rotation Question with Solution | TestHub

Given: horizontal force $F=100$ N, mass $m=20$ kg, floor smooth ($\mu =0$).

The only horizontal external force on the cabinet is $F$.

$a=\frac{F}{m}=\frac{100}{20}=5{\text{ m/s}}^2$

(The height at which $F$ acts and the cabinet dimensions affect the normal reactions / tendency to tip, not the acceleration of the centre of mass.)

Answer: (A) 5