A hoop of radius r and mass m rotating with an angular velocity ω 0 is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the ce

Question

A hoop of radius r and mass m rotating with an angular velocity ω 0 is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the hoop when it ceases to slip?

TestHub · Accepted Answer

By conservation of angular momentum at the point of contact m r 2 ω 0 = m v r + m r 2 ω = m v r + m r 2 . v / r ⇒ r 2 ω 0 = 2 v r ⇒ v = r ω 0 / 2

Physics - Rotation Question with Solution | TestHub

Options:

Doubts & Discussion