Physics - Rotation Question with Solution | TestHub

PhysicsRotationAngular momentumEasy2 minQB
PhysicsEasynumerical

A block of mass0.1 kgis attached to a cord passing through a hole in a horizontal frictionless horizontal surface as shown in the figure. The block is originally revolving at a distance of0.4 mfrom the hole, with an angular velocity of2 rad s-1. The cord is then pulled from below, shortening the radius of the circle in which the block revolves to0.2 m. Considering the block to be point mass, calculate the new angular velocity (inrad s-1).

Answer:
8.00
Solution:

By conservation of angular momentum

I1ω1=I2ω2

⇒   MR12ω1=MR22ω2

⇒   ω2=R1R22ω1

=0.40.22×2

=8 rad s-1

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Angular momentum
⏱ 2mℹ️ Source: QB

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