Physics - Rotation Question with Solution | TestHub

$\mathrm{Here, }{\omega }_0=0\text{;}\theta =400\text{rad}\text{;}t=10s$

$\text{Now,}\theta ={\omega }_{0}t+\frac{1}{2}\alpha t^2\dots \left(i\right)$

$\therefore 400=0\times 10+\frac{1}{2}\alpha \times 10^2$

$\text{or}\alpha =\frac{400\times 2}{10^2}$

$\text{or}\alpha =8{\text{rad s}}^{-2}$