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Physics - Rotation Question with Solution | TestHub

PhysicsRotationTranslational + RotationalMedium2 minPYQ_2020

PhysicsMediumsingle choice

A solid cylinder of radius 'R' and mass 'M' rolls down an inclined plane of height 'h'. When it reaches the bottom of the plane, its rotational kinetic energy is $(g =$ acceleration due to gravity)

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Answer:

Solution:

$Total KE = \frac{1}{2} Mv^{2} + \frac{1}{2} I ω^{2} = \frac{1}{2} Mv^{2} + \frac{1}{2} (\frac{1}{2} MR^{2}) v^{2} = \frac{1}{2} Mv^{2} + \frac{1}{4} Mv^{2} = \frac{3}{4} Mv^{2} = Mgh$

Stream:MHT_CETSubject:PhysicsTopic:RotationSubtopic:Translational + Rotational

⏱ 2mℹ️ Source: PYQ_2020

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