Physics - Rotation Question with Solution | TestHub

For a light string over each ideal pulley, the tension is the same on both sides.

Left pulley: total downward force = m₁g + 2m₁g = 3m₁g.

Right pulley: total downward force = 4m₂g + 2m₂g = 6m₂g.

Taking moments about the suspension point of the rod:

$$(3m_{1}g)(\ell /3)=(6m_{2}g)(2\ell /3)$$

Therefore m₁ = 4m₂, so m₁/m₂ = 4.