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PhysicsRotationAngular momentumHard2 minPYQ_2019
PhysicsHardsingle choice

A person of massMis sitting on a swing of lengthLand swinging with and an angular amplitudeθ0.If the person stands up when the swing passes through its lowest point, the work done by him, assuming that his centre of mass moves by a distancel l<<L,is close to:

Options:

Answer:
D
Solution:

From angular momentum conservation
MV0L=MV(L-l)V=V0LL-l
Now
W=Mgl+12MV02LL-l2-V02
SincelL
W=Mgl+12MV021-lL-2-V02=Mgl+12MV021+2lL-V02=Mgl+MV02lL
From SHM
V0=ωA=gL×Lθ0=gLθ0
Using this
W=Mgl+MgL×θ02×lLW=Mgl1+θ02

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Angular momentum
2mℹ️ Source: PYQ_2019

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