A triangular plate is shown. A force F → = 4 i ^ - 3 j ^ is applied at point P . The torque at point P with respect to point O and Q are:

F → = 4 i ^ - 3 j ^ r → 1 = 5 i ^ + 5 3 j ^ and r → 2 = - 5 i ^ + 5 3 j ^ Torque about ' O ' τ → O = r → 1 × F → = - 15 - 20 3 k ^ Torque about ' Q ' τ → Q = r → 2 × F → = 15 - 20 3 k ^

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Physics - Rotation Question with Solution | TestHub

PhysicsRotationTorque / angular accelerationMedium2 minPYQ_2021

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A triangular plate is shown. A force $\vec{F} = 4 \hat{i} - 3 \hat{j}$ is applied at point $P .$ The torque at point $P$ with respect to point $O$ and $Q$ are:

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Answer:

Solution:

$\vec{F} = 4 \hat{i} - 3 \hat{j}$

${\vec{r}}_{1} = 5 \hat{i} + 5 \sqrt{3} \hat{j}$ and ${\vec{r}}_{2} = - 5 \hat{i} + 5 \sqrt{3} \hat{j}$

Torque about $' O'$

${\vec{τ}}_{O} = {\vec{r}}_{1} \times \vec{F} = (- 15 - 20 \sqrt{3}) \hat{k}$

Torque about $' Q'$

${\vec{τ}}_{Q} = {\vec{r}}_{2} \times \vec{F} = (15 - 20 \sqrt{3}) \hat{k}$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Torque / angular acceleration

⏱ 2mℹ️ Source: PYQ_2021

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