Physics - Capacitor Question with Solution | TestHub

In an R-C circuit, we can find heat dissipated (Q) by using the equation $W_b=\Delta U+Q$ Where, $W_b=$ work done by all the sources when charges flow through them and, $\Delta U=$ change in electrostatic potential energy of the system of capacitors. In the given circuit at time $\mathrm{t}=0$, let us close the key K . Assume $q_0=2\mu \mathrm{C}$, $C_1=10^{-6}\mathrm{F},C_2=0.5\times 10^{-6}\mathrm{F},R=2\Omega$ and $\epsilon =4V$,