Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorBasic capacitor analysis with dielectricHard2 minPYQ_2014
PhysicsHardsingle choice

Two thin dielectric slabs of dielectric constantsK1andK2K1<K2are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field ‘E’ between the plates with distance ‘d’ as measured from platePis correctly shown by:
NEET 2014

Options:

Answer:
C
Solution:

Here we have to calculate the graph between E and d in the given situation

We know that in dielectric E becomes E/k 

where

E = Electric fjeld 

k = Dielectric constants

Since K1<K2, The third option will be correct.

Stream:NEETSubject:PhysicsTopic:CapacitorSubtopic:Basic capacitor analysis with dielectric
⏱ 2mℹ️ Source: PYQ_2014

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