What is the energy stored in the capacitor between terminals $a$ and $b$ of the network shown in the figure? (Capacitance of each capacitor $C = 1 μ F)$

Question

What is the energy stored in the capacitor between terminals a and b of the network shown in the figure? (Capacitance of each capacitor C = 1 μ F )

TestHub · Accepted Answer

Network is redrawn as shown in figure.
This is a balanced Wheatstone's network. Equivalent capacitance $C_{e q} = C$ Charge on capacitor between the terminals $a$ and $b$ $\frac{Q}{2} = \frac{C V}{2}$ Energy stored in that capacitor
$= \frac{1 ( \frac{Q}{2} ) ^{2}}{2 C} = \frac{Q ^{2}}{8 C} = \frac{C ^{2} V ^{2}}{8 C} = \frac{C V ^{2}}{8}$ Given: $C = 1 μ F, V = 10 V$ $= \frac{( 1 \times 1 0 ^{- 6} ) \times 1 0 ^{2}}{8} = \frac{100}{8} \times 1 0^{- 6} = 12.5 μ J$

Physics - Capacitor Question with Solution | TestHub

Options:

Doubts & Discussion