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Physics - Rotation Question with Solution | TestHub

PhysicsRotationMiscellaneousMedium3 minQB

PhysicsMediuminteger

A uniform rod of length $l$ and mass $m = 4 kg$ rests on supports at its ends. The right support is quickly removed (see figure). What is the force (in N) on the left support immediately thereafter?

CT42 n2 diagram

Answer:

Solution:

Immediately after the right support is removed, $m gL /2 = (m L^{2} /3) α$ , so $α = 3 g / (2 L)$ .

The centre-of-mass acceleration is $a = αL /2 = 3 g /4$ downward.

$m g - N = m (3 g /4)$ , giving $N = m g /4 = 10 N$ .

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Miscellaneous

⏱ 3mℹ️ Source: QB

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