Four equal masses, m each are placed at the corners of a square of length l as shown in the figure. The moment of inertia of the system about an axis passing through A and parallel to D B would be :

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TestHub · Accepted Answer

Moment of inertia of point mass = mass × Perpendicular distance from axis 2 Moment of Inertia = m 0 2 + m l 2 2 + m l 2 2 + m l 2 2 = 3 m l 2

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